6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
|
# File 'lib/puppet/parser/functions/getparam.rb', line 6
Puppet::Parser::Functions.newfunction(:getparam,
type: :rvalue,
doc: <<-'DOC',
@summary
Returns the value of a resource's parameter.
@return
value of a resource's parameter.
Takes a resource reference and name of the parameter and
returns value of resource's parameter. Note that user defined
resource types are evaluated lazily.
@example Example Usage:
# define a resource type with a parameter
define example_resource($param) {
}
# declare an instance of that type
example_resource { "example_resource_instance":
param => "'the value we are getting in this example''"
}
# Because of order of evaluation, a second definition is needed
# that will be evaluated after the first resource has been declared
#
define example_get_param {
# This will notice the value of the parameter
notice(getparam(Example_resource["example_resource_instance"], "param"))
}
# Declare an instance of the second resource type - this will call notice
example_get_param { 'show_notify': }
Would notice: 'the value we are getting in this example'
> **Note** that since Puppet 4.0.0 it is possible to get a parameter value by using its data type
and the [ ] operator. The example below is equivalent to a call to getparam():
```Example_resource['example_resource_instance']['param']``
DOC
) do |vals|
reference, param = vals
raise(ArgumentError, 'Must specify a reference') unless reference
raise(ArgumentError, 'Must specify name of a parameter') unless param&.instance_of?(String)
return '' if param.empty?
resource = findresource(reference.to_s)
if resource
return resource[param] unless resource[param].nil?
end
return ''
end
|